桑塔纳2000防盗电脑数据算法
3 q: X) Z' o$ j6 s* I- G时代超人防盗密码技术解析% i; _0 }& T: W q
通过编程器怎样从防盗盒中读取密码。
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1 Q+ y# g' s3 S, Y( e8 K4 _下面就从时代超人为例给大家共享。时代超人存储密码的芯片是Microchip微晶公司的93LC56,其数据密码是9806。6 E) M+ g' x1 Y$ w3 `+ s
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00000000h: (54 74 99 2E) (A7 40 02 43) (C1 98 99 2E) 00 00 00 00" f) r, m4 C3 N7 A3 U; O$ o
00000010h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00! X# F) t( l% b* L5 X
00000020h: D9 A4 60 D3 B1 (26 4E) 25 09 51 36 58 90 02 37 06
/ ]1 c3 |% X6 z/ L00000030h: 2A (33) 00 1E 14 00 A0 00 00 00 00 00 00 00 00 00
1 _/ |* I, Q0 y- P7 g$ f S00000040h: 54 74 99 2E A7 40 02 43 C1 98 99 2E 00 00 00 00/ x& |4 \% x; W- f" F
00000050h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
- G6 S& q" x+ u( ]00000060h: D9 A4 60 D3 B1 (26 4E)25 09 51 36 58 90 02 37 00
: o: T7 |9 ?4 I( ?) K/ f00000070h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
- p) ?' n. ^" N [# k4 F00000080h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 001 W9 r# K2 Z! ] \& S5 F" i2 g- Q
00000090h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 009 J5 j1 S1 | ?# {' t
000000a0h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 006 O! g5 v0 ^+ Z( C
000000b0h: 59 34 22 74 38 02 20 00 00 00 00 00 00 00 00 00+ ]3 L+ e2 o! h6 x0 ^/ T" [& ]6 p, Y7 c
000000c0h: 54 74 99 2E A7 40 02 43 C1 98 99 2E 00 00 00 00
; N3 }( m' ?, k$ q000000d0h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
' r3 q) d- {3 _ z9 ]) J: J000000e0h: D9 A4 60 D3 B1 (26 4E)25 09 51 36 58 90 02 37 00
4 H) c9 a1 g, h2 s000000f0h: 00 00 00 00 05 18 00 95 00 51 01 90 05 00 20 01: ~+ c1 G5 ~9 I! D8 _- |+ m/ c
3 ~0 t$ f- q) E% p6 G密码位置在025H.026H和065H.066H和e5H.e6H重复三遍.3 d m" C' z4 r3 m
上述数据十六进制26 4E变成十进制9806为防盗登录密码.. x- q } z, h) _1 R" w
如果03H处是03为登录密码错3次,这时要打开点火开关等待30分钟以上.如果改成00就无须等待.
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8 X' ?. s" d5 w000-01F为记录钥匙.1 b3 m9 P5 r' y F' f& r5 q
54 74 99 2E 第一把钥匙,6 |, E( ?3 n! X
A7 40 02 43 第二把钥匙,! e& t! _- t1 J+ `- T) x% `
C1 98 99 2E第三把钥匙.- p# v- Z/ a+ f/ H/ `5 n( D" g5 O( _
以此类推。0 q: e6 {4 `$ S. H
00 00 00 00说明没有适配钥匙.. V! o. k4 A) x
031H处33说明适配了3把钥匙,如果是55适配了5把钥匙.
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