桑塔纳2000防盗电脑数据算法' f& z, a/ E; E! K& M+ d7 Y
时代超人防盗密码技术解析: ?: E) w( Y) U% S, N- ]! `
通过编程器怎样从防盗盒中读取密码。/ s( v6 y' A& O6 M' L
- d9 b1 X0 I7 _2 |0 \下面就从时代超人为例给大家共享。时代超人存储密码的芯片是Microchip微晶公司的93LC56,其数据密码是9806。. Y' ?+ P5 u: Z
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00000000h: (54 74 99 2E) (A7 40 02 43) (C1 98 99 2E) 00 00 00 00% v% U5 e9 t8 t* g$ w8 f; h4 R9 g: w
00000010h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
8 [* L8 B7 p0 s m00000020h: D9 A4 60 D3 B1 (26 4E) 25 09 51 36 58 90 02 37 063 C, E5 R" f5 Z: V( x
00000030h: 2A (33) 00 1E 14 00 A0 00 00 00 00 00 00 00 00 00! ~( V" T; i* h
00000040h: 54 74 99 2E A7 40 02 43 C1 98 99 2E 00 00 00 008 y+ H* G0 M* P; p+ f! N" s
00000050h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
4 n" |3 L* b" T% G( z' B00000060h: D9 A4 60 D3 B1 (26 4E)25 09 51 36 58 90 02 37 00
& U" ^$ Y0 w9 o3 v d$ G" k00000070h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
* u2 P i2 m* i* j+ q- m, G! ^00000080h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00; w! u% I, n" s t6 O, `9 [, V1 M S4 V
00000090h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00: Z: H' R8 R# M' }. A; X
000000a0h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
7 [% z7 J! C% q7 [000000b0h: 59 34 22 74 38 02 20 00 00 00 00 00 00 00 00 00. C0 I: J5 R7 E( M* |: h" o3 \
000000c0h: 54 74 99 2E A7 40 02 43 C1 98 99 2E 00 00 00 006 T' W, b4 P3 d0 j6 x
000000d0h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00* R* W1 ]# z3 Y8 j% Y+ W0 ?. a/ y+ Q
000000e0h: D9 A4 60 D3 B1 (26 4E)25 09 51 36 58 90 02 37 00
0 F! @* j2 k/ h( i/ q" T# X000000f0h: 00 00 00 00 05 18 00 95 00 51 01 90 05 00 20 01' I9 C6 w# n6 M, c
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密码位置在025H.026H和065H.066H和e5H.e6H重复三遍.
. Z' h! ^5 E2 h. z2 l上述数据十六进制26 4E变成十进制9806为防盗登录密码.
}( a, i- L; x" b X如果03H处是03为登录密码错3次,这时要打开点火开关等待30分钟以上.如果改成00就无须等待.
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" ]; a# r, z# n0 G000-01F为记录钥匙.2 b- X4 V; x8 ~, J4 W8 |! {
54 74 99 2E 第一把钥匙,
( V) l8 X' S% a& \9 WA7 40 02 43 第二把钥匙,$ ^2 f7 K4 A$ g y' e: X- k `" o
C1 98 99 2E第三把钥匙.
~4 ~( T; u; c6 \1 ]以此类推。' G7 C: u6 i& [& L* e& T
00 00 00 00说明没有适配钥匙.
! O* Q+ b" B! ]4 i$ m031H处33说明适配了3把钥匙,如果是55适配了5把钥匙.* w* l, d2 R7 u1 Z
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