桑塔纳2000防盗电脑数据算法
" U' k, K0 Q) z时代超人防盗密码技术解析- w3 l r1 a; a
通过编程器怎样从防盗盒中读取密码。
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下面就从时代超人为例给大家共享。时代超人存储密码的芯片是Microchip微晶公司的93LC56,其数据密码是9806。
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) U' J' a4 m9 ]# G% z$ ^3 a00000000h: (54 74 99 2E) (A7 40 02 43) (C1 98 99 2E) 00 00 00 00
! R: W/ k# ~6 c: I, K- }$ q; M00000010h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 000 G5 d' b# Q8 o7 N0 @8 t# E# A
00000020h: D9 A4 60 D3 B1 (26 4E) 25 09 51 36 58 90 02 37 06
) {+ A; {( j9 F2 w5 A00000030h: 2A (33) 00 1E 14 00 A0 00 00 00 00 00 00 00 00 00
K& j) D% Y- T- T0 u( N4 g# c00000040h: 54 74 99 2E A7 40 02 43 C1 98 99 2E 00 00 00 00
5 l- D! x3 E% D. Z/ f00000050h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00$ a. M' T# h% f& d
00000060h: D9 A4 60 D3 B1 (26 4E)25 09 51 36 58 90 02 37 00
2 U3 j' d8 g8 a- J$ R7 v8 h0 x7 ?00000070h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
' N7 A, W2 ?' y9 Z" [0 s4 @5 l00000080h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
8 i. _4 F) N- I9 W6 L00000090h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00* J% x o! t: N1 X" o
000000a0h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
. h5 g0 X6 s9 n000000b0h: 59 34 22 74 38 02 20 00 00 00 00 00 00 00 00 004 p6 F& y' Y, u, x
000000c0h: 54 74 99 2E A7 40 02 43 C1 98 99 2E 00 00 00 00
' J8 g6 A, N( k+ w- c/ k E000000d0h: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
1 c% m8 I4 k h/ r000000e0h: D9 A4 60 D3 B1 (26 4E)25 09 51 36 58 90 02 37 001 h1 F2 G' `/ h
000000f0h: 00 00 00 00 05 18 00 95 00 51 01 90 05 00 20 01" d4 I/ o% V- X4 G% E' I% e5 ~
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密码位置在025H.026H和065H.066H和e5H.e6H重复三遍.7 z7 O* y* N8 e2 k
上述数据十六进制26 4E变成十进制9806为防盗登录密码.
; L0 L% c) d: e7 U' b" |2 L! K5 X如果03H处是03为登录密码错3次,这时要打开点火开关等待30分钟以上.如果改成00就无须等待.# F m5 Z) @9 ^) O1 O
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000-01F为记录钥匙.
|/ C& O% w( a9 F, L2 e) I+ a54 74 99 2E 第一把钥匙,
" X! W0 @0 m. V' q/ J. v% EA7 40 02 43 第二把钥匙,
& [ P, M) ~) q7 @5 @" WC1 98 99 2E第三把钥匙.9 {0 x3 F. u8 X, C( P- T
以此类推。
9 K! q |& ?- z G, `$ z* _2 |' Q00 00 00 00说明没有适配钥匙.
- T7 L: \" c# r+ q# \1 x/ Q031H处33说明适配了3把钥匙,如果是55适配了5把钥匙.+ h$ x- q3 K1 w7 K2 @' h; Q
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